c – Why doesn’t this compile in C18? – Education Career Blog

I’m trying to compile the following code using the MPLAB C18 v3.36 compiler.

Compiler returns a syntax error on ‘char rij;’.
But when i put char rij; a line earlier (before TRISA = …), it compiles …

void setup(void)
 TRISD = 0b00000000;
 TRISA = 0b00000000;
 char rij;
 for (rij = 0; rij<ROWS; rij++)


Although I’m not familiar with this compiler I would guess that it follows C89 semantics which forbid mixing declarations with statements. Therefore you can only declare variables on the beginning of the block.

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