jquery $(document).ready() queue order – Education Career Blog

I have a page index.html that extends base.html (django) and each of them has a $(document).ready defined. Now, I was expecting the one in base.html to go of first, but I was wrong, the one in index is first and the one in base.html starts after. I guess this is because index finishes loading before base, and not some default behavior of jquery, to have children execute before the parent. Can I do something to change this order? Because the parent decides (depending on window size) if the menu should be vertical or horizontal, and the child scales a div to occupy the rest of the window. Now I would like the scaling to occur after I have the menu in place.

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You could theoretically change this by manipulating the jQuery.readyList array and moving things around, but you’d be poking a bit blind in there. Instead I’d recommend switching your script that needs to run after the others from document.ready to window.onload, like this:

$(window).load(function() {
  //code to run after the others
});

It seems you’d want this anyway, since you’re dealing with window size and scaling, and this happens after the images are loaded, so your scale would be correct, not still changing.

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