python – Parsing a list into a url string – Education Career Blog

I have a list of tags that I would like to add to a url string, separated by commas (‘%2C’). How can I do this ? I was trying :

>>> tags_list
'tag1', ' tag2'
>>> parse_string = "" % (lambda x: "%s," %x for x in tags_list)

but received a generator :

>>> parse_string
'http://<generator object <genexpr> at 0x02751F58>'

Also do I need to change commas to %2C? I need it to feedpaarser to parse results. If yes – how can I insert those tags separated by this special sign ?


parse_string = ""
for x in tags_list:
    parse_string += "%s," % x

but can I escape this %2C ? Also I’m pretty sure there is a shorter ‘lambda’ way 🙂


parse_string = ("" % 
               '%2C'.join(tag.strip() for tag in tags_list))

Results in:

>>> parse_string = ("" %
...                '%2C'.join(tag.strip() for tag in tags_list))
>>> parse_string

Side note:
Going forward I think you want to use format() for string interpolation, e.g.:

>>> parse_string = "{0}&restofurl".format(
...                '%2C'.join(tag.strip() for tag in tags_list))
>>> parse_string


"%s" is fine, but urlparse.urlunparse after urllib.urlencode is safer.

str.join is fine, but remember to check your tags for commas and number signs, or use urllib.quote on each one.

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